-3(3y+2)-4(y-2)=

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Solution for -3(3y+2)-4(y-2)= equation:


Simplifying
-3(3y + 2) + -4(y + -2) = 0

Reorder the terms:
-3(2 + 3y) + -4(y + -2) = 0
(2 * -3 + 3y * -3) + -4(y + -2) = 0
(-6 + -9y) + -4(y + -2) = 0

Reorder the terms:
-6 + -9y + -4(-2 + y) = 0
-6 + -9y + (-2 * -4 + y * -4) = 0
-6 + -9y + (8 + -4y) = 0

Reorder the terms:
-6 + 8 + -9y + -4y = 0

Combine like terms: -6 + 8 = 2
2 + -9y + -4y = 0

Combine like terms: -9y + -4y = -13y
2 + -13y = 0

Solving
2 + -13y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -13y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -13y = 0 + -2
-13y = 0 + -2

Combine like terms: 0 + -2 = -2
-13y = -2

Divide each side by '-13'.
y = 0.1538461538

Simplifying
y = 0.1538461538

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