-3(3y-1)+7y=4+3(2y-5)

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Solution for -3(3y-1)+7y=4+3(2y-5) equation:



-3(3y-1)+7y=4+3(2y-5)
We move all terms to the left:
-3(3y-1)+7y-(4+3(2y-5))=0
We add all the numbers together, and all the variables
7y-3(3y-1)-(4+3(2y-5))=0
We multiply parentheses
7y-9y-(4+3(2y-5))+3=0
We calculate terms in parentheses: -(4+3(2y-5)), so:
4+3(2y-5)
determiningTheFunctionDomain 3(2y-5)+4
We multiply parentheses
6y-15+4
We add all the numbers together, and all the variables
6y-11
Back to the equation:
-(6y-11)
We add all the numbers together, and all the variables
-2y-(6y-11)+3=0
We get rid of parentheses
-2y-6y+11+3=0
We add all the numbers together, and all the variables
-8y+14=0
We move all terms containing y to the left, all other terms to the right
-8y=-14
y=-14/-8
y=1+3/4

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