-3(3y-10)-y=-4(y-2)

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Solution for -3(3y-10)-y=-4(y-2) equation: 



-3(3y-10)-y=-4(y-2)

We move all terms to the left:

-3(3y-10)-y-(-4(y-2))=0

We add all the numbers together, and all the variables

-1y-3(3y-10)-(-4(y-2))=0

We multiply parentheses

-1y-9y-(-4(y-2))+30=0



We calculate terms in parentheses: -(-4(y-2)), so:

-4(y-2)

We multiply parentheses

-4y+8

Back to the equation:

-(-4y+8)



We add all the numbers together, and all the variables

-10y-(-4y+8)+30=0

We get rid of parentheses

-10y+4y-8+30=0

We add all the numbers together, and all the variables

-6y+22=0

We move all terms containing y to the left, all other terms to the right

-6y=-22

y=-22/-6

y=3+2/3

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