-3(3y-2)+3y=3(y+3)

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Solution for -3(3y-2)+3y=3(y+3) equation: 



-3(3y-2)+3y=3(y+3)

We move all terms to the left:

-3(3y-2)+3y-(3(y+3))=0

We add all the numbers together, and all the variables

3y-3(3y-2)-(3(y+3))=0

We multiply parentheses

3y-9y-(3(y+3))+6=0



We calculate terms in parentheses: -(3(y+3)), so:

3(y+3)

We multiply parentheses

3y+9

Back to the equation:

-(3y+9)



We add all the numbers together, and all the variables

-6y-(3y+9)+6=0

We get rid of parentheses

-6y-3y-9+6=0

We add all the numbers together, and all the variables

-9y-3=0

We move all terms containing y to the left, all other terms to the right

-9y=3

y=3/-9

y=-1/3

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