-3(3y-2)+y=2(y+7)

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Solution for -3(3y-2)+y=2(y+7) equation: 



-3(3y-2)+y=2(y+7)

We move all terms to the left:

-3(3y-2)+y-(2(y+7))=0

We add all the numbers together, and all the variables

y-3(3y-2)-(2(y+7))=0

We multiply parentheses

y-9y-(2(y+7))+6=0



We calculate terms in parentheses: -(2(y+7)), so:

2(y+7)

We multiply parentheses

2y+14

Back to the equation:

-(2y+14)



We add all the numbers together, and all the variables

-8y-(2y+14)+6=0

We get rid of parentheses

-8y-2y-14+6=0

We add all the numbers together, and all the variables

-10y-8=0

We move all terms containing y to the left, all other terms to the right

-10y=8

y=8/-10

y=-4/5

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