-3(3y-2)-y=-4(y-4)

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Solution for -3(3y-2)-y=-4(y-4) equation: 



-3(3y-2)-y=-4(y-4)

We move all terms to the left:

-3(3y-2)-y-(-4(y-4))=0

We add all the numbers together, and all the variables

-1y-3(3y-2)-(-4(y-4))=0

We multiply parentheses

-1y-9y-(-4(y-4))+6=0



We calculate terms in parentheses: -(-4(y-4)), so:

-4(y-4)

We multiply parentheses

-4y+16

Back to the equation:

-(-4y+16)



We add all the numbers together, and all the variables

-10y-(-4y+16)+6=0

We get rid of parentheses

-10y+4y-16+6=0

We add all the numbers together, and all the variables

-6y-10=0

We move all terms containing y to the left, all other terms to the right

-6y=10

y=10/-6

y=-1+2/3

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