-3(3y-3)+3y=6(y+4)

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Solution for -3(3y-3)+3y=6(y+4) equation: 



-3(3y-3)+3y=6(y+4)

We move all terms to the left:

-3(3y-3)+3y-(6(y+4))=0

We add all the numbers together, and all the variables

3y-3(3y-3)-(6(y+4))=0

We multiply parentheses

3y-9y-(6(y+4))+9=0



We calculate terms in parentheses: -(6(y+4)), so:

6(y+4)

We multiply parentheses

6y+24

Back to the equation:

-(6y+24)



We add all the numbers together, and all the variables

-6y-(6y+24)+9=0

We get rid of parentheses

-6y-6y-24+9=0

We add all the numbers together, and all the variables

-12y-15=0

We move all terms containing y to the left, all other terms to the right

-12y=15

y=15/-12

y=-1+1/4

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