-3(3y-3)-y=-3(y-2)

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Solution for -3(3y-3)-y=-3(y-2) equation: 



-3(3y-3)-y=-3(y-2)

We move all terms to the left:

-3(3y-3)-y-(-3(y-2))=0

We add all the numbers together, and all the variables

-1y-3(3y-3)-(-3(y-2))=0

We multiply parentheses

-1y-9y-(-3(y-2))+9=0



We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We add all the numbers together, and all the variables

-10y-(-3y+6)+9=0

We get rid of parentheses

-10y+3y-6+9=0

We add all the numbers together, and all the variables

-7y+3=0

We move all terms containing y to the left, all other terms to the right

-7y=-3

y=-3/-7

y=3/7

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