-3(3y-3)-y=-4(y-5)

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Solution for -3(3y-3)-y=-4(y-5) equation: 



-3(3y-3)-y=-4(y-5)

We move all terms to the left:

-3(3y-3)-y-(-4(y-5))=0

We add all the numbers together, and all the variables

-1y-3(3y-3)-(-4(y-5))=0

We multiply parentheses

-1y-9y-(-4(y-5))+9=0



We calculate terms in parentheses: -(-4(y-5)), so:

-4(y-5)

We multiply parentheses

-4y+20

Back to the equation:

-(-4y+20)



We add all the numbers together, and all the variables

-10y-(-4y+20)+9=0

We get rid of parentheses

-10y+4y-20+9=0

We add all the numbers together, and all the variables

-6y-11=0

We move all terms containing y to the left, all other terms to the right

-6y=11

y=11/-6

y=-1+5/6

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