-3(3y-4)+6y=7+3(5y-3)

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Solution for -3(3y-4)+6y=7+3(5y-3) equation: 



-3(3y-4)+6y=7+3(5y-3)

We move all terms to the left:

-3(3y-4)+6y-(7+3(5y-3))=0

We add all the numbers together, and all the variables

6y-3(3y-4)-(7+3(5y-3))=0

We multiply parentheses

6y-9y-(7+3(5y-3))+12=0



We calculate terms in parentheses: -(7+3(5y-3)), so:

7+3(5y-3)

determiningTheFunctionDomain
3(5y-3)+7

We multiply parentheses

15y-9+7

We add all the numbers together, and all the variables

15y-2

Back to the equation:

-(15y-2)



We add all the numbers together, and all the variables

-3y-(15y-2)+12=0

We get rid of parentheses

-3y-15y+2+12=0

We add all the numbers together, and all the variables

-18y+14=0

We move all terms containing y to the left, all other terms to the right

-18y=-14

y=-14/-18

y=7/9

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