-3(3y-4)-y=-3(y-2)

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Solution for -3(3y-4)-y=-3(y-2) equation:



-3(3y-4)-y=-3(y-2)
We move all terms to the left:
-3(3y-4)-y-(-3(y-2))=0
We add all the numbers together, and all the variables
-1y-3(3y-4)-(-3(y-2))=0
We multiply parentheses
-1y-9y-(-3(y-2))+12=0
We calculate terms in parentheses: -(-3(y-2)), so:
-3(y-2)
We multiply parentheses
-3y+6
Back to the equation:
-(-3y+6)
We add all the numbers together, and all the variables
-10y-(-3y+6)+12=0
We get rid of parentheses
-10y+3y-6+12=0
We add all the numbers together, and all the variables
-7y+6=0
We move all terms containing y to the left, all other terms to the right
-7y=-6
y=-6/-7
y=6/7

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