-3(3y-4)-y=-3(y-3)

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Solution for -3(3y-4)-y=-3(y-3) equation:



-3(3y-4)-y=-3(y-3)
We move all terms to the left:
-3(3y-4)-y-(-3(y-3))=0
We add all the numbers together, and all the variables
-1y-3(3y-4)-(-3(y-3))=0
We multiply parentheses
-1y-9y-(-3(y-3))+12=0
We calculate terms in parentheses: -(-3(y-3)), so:
-3(y-3)
We multiply parentheses
-3y+9
Back to the equation:
-(-3y+9)
We add all the numbers together, and all the variables
-10y-(-3y+9)+12=0
We get rid of parentheses
-10y+3y-9+12=0
We add all the numbers together, and all the variables
-7y+3=0
We move all terms containing y to the left, all other terms to the right
-7y=-3
y=-3/-7
y=3/7

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