-3(3y-5)-y=-2(y-2)

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Solution for -3(3y-5)-y=-2(y-2) equation: 



-3(3y-5)-y=-2(y-2)

We move all terms to the left:

-3(3y-5)-y-(-2(y-2))=0

We add all the numbers together, and all the variables

-1y-3(3y-5)-(-2(y-2))=0

We multiply parentheses

-1y-9y-(-2(y-2))+15=0



We calculate terms in parentheses: -(-2(y-2)), so:

-2(y-2)

We multiply parentheses

-2y+4

Back to the equation:

-(-2y+4)



We add all the numbers together, and all the variables

-10y-(-2y+4)+15=0

We get rid of parentheses

-10y+2y-4+15=0

We add all the numbers together, and all the variables

-8y+11=0

We move all terms containing y to the left, all other terms to the right

-8y=-11

y=-11/-8

y=1+3/8

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