-3(3y-6)-y=-4(y-5)

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Solution for -3(3y-6)-y=-4(y-5) equation:



-3(3y-6)-y=-4(y-5)
We move all terms to the left:
-3(3y-6)-y-(-4(y-5))=0
We add all the numbers together, and all the variables
-1y-3(3y-6)-(-4(y-5))=0
We multiply parentheses
-1y-9y-(-4(y-5))+18=0
We calculate terms in parentheses: -(-4(y-5)), so:
-4(y-5)
We multiply parentheses
-4y+20
Back to the equation:
-(-4y+20)
We add all the numbers together, and all the variables
-10y-(-4y+20)+18=0
We get rid of parentheses
-10y+4y-20+18=0
We add all the numbers together, and all the variables
-6y-2=0
We move all terms containing y to the left, all other terms to the right
-6y=2
y=2/-6
y=-1/3

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