-3(3y-6)-y=4(y-2)

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Solution for -3(3y-6)-y=4(y-2) equation: 



-3(3y-6)-y=4(y-2)

We move all terms to the left:

-3(3y-6)-y-(4(y-2))=0

We add all the numbers together, and all the variables

-1y-3(3y-6)-(4(y-2))=0

We multiply parentheses

-1y-9y-(4(y-2))+18=0



We calculate terms in parentheses: -(4(y-2)), so:

4(y-2)

We multiply parentheses

4y-8

Back to the equation:

-(4y-8)



We add all the numbers together, and all the variables

-10y-(4y-8)+18=0

We get rid of parentheses

-10y-4y+8+18=0

We add all the numbers together, and all the variables

-14y+26=0

We move all terms containing y to the left, all other terms to the right

-14y=-26

y=-26/-14

y=1+6/7

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