-3(3y-7)-y=3(y-3)

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Solution for -3(3y-7)-y=3(y-3) equation: 



-3(3y-7)-y=3(y-3)

We move all terms to the left:

-3(3y-7)-y-(3(y-3))=0

We add all the numbers together, and all the variables

-1y-3(3y-7)-(3(y-3))=0

We multiply parentheses

-1y-9y-(3(y-3))+21=0



We calculate terms in parentheses: -(3(y-3)), so:

3(y-3)

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)



We add all the numbers together, and all the variables

-10y-(3y-9)+21=0

We get rid of parentheses

-10y-3y+9+21=0

We add all the numbers together, and all the variables

-13y+30=0

We move all terms containing y to the left, all other terms to the right

-13y=-30

y=-30/-13

y=2+4/13

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