-3(3z+4)=6z-3(3+2)

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Solution for -3(3z+4)=6z-3(3+2) equation: 



-3(3z+4)=6z-3(3+2)

We move all terms to the left:

-3(3z+4)-(6z-3(3+2))=0

We add all the numbers together, and all the variables

-3(3z+4)-(6z-35)=0

We multiply parentheses

-9z-(6z-35)-12=0

We get rid of parentheses

-9z-6z+35-12=0

We add all the numbers together, and all the variables

-15z+23=0

We move all terms containing z to the left, all other terms to the right

-15z=-23

z=-23/-15

z=1+8/15

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