-3(4+10a)=-3(12a-12)

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Solution for -3(4+10a)=-3(12a-12) equation: 



-3(4+10a)=-3(12a-12)

We move all terms to the left:

-3(4+10a)-(-3(12a-12))=0

We add all the numbers together, and all the variables

-3(10a+4)-(-3(12a-12))=0

We multiply parentheses

-30a-(-3(12a-12))-12=0



We calculate terms in parentheses: -(-3(12a-12)), so:

-3(12a-12)

We multiply parentheses

-36a+36

Back to the equation:

-(-36a+36)



We get rid of parentheses

-30a+36a-36-12=0

We add all the numbers together, and all the variables

6a-48=0

We move all terms containing a to the left, all other terms to the right

6a=48

a=48/6

a=8

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