-3(4+r)+3=-(4+2r)-2r

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Solution for -3(4+r)+3=-(4+2r)-2r equation: 



-3(4+r)+3=-(4+2r)-2r

We move all terms to the left:

-3(4+r)+3-(-(4+2r)-2r)=0

We add all the numbers together, and all the variables

-3(r+4)-(-(2r+4)-2r)+3=0

We multiply parentheses

-3r-(-(2r+4)-2r)-12+3=0



We calculate terms in parentheses: -(-(2r+4)-2r), so:

-(2r+4)-2r

We add all the numbers together, and all the variables

-2r-(2r+4)

We get rid of parentheses

-2r-2r-4

We add all the numbers together, and all the variables

-4r-4

Back to the equation:

-(-4r-4)



We add all the numbers together, and all the variables

-3r-(-4r-4)-9=0

We get rid of parentheses

-3r+4r+4-9=0

We add all the numbers together, and all the variables

r-5=0

We move all terms containing r to the left, all other terms to the right

r=5

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