-3(4-(3b+3))=4-3(3b+7)

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Solution for -3(4-(3b+3))=4-3(3b+7) equation: 



-3(4-(3b+3))=4-3(3b+7)

We move all terms to the left:

-3(4-(3b+3))-(4-3(3b+7))=0



We calculate terms in parentheses: -(4-3(3b+7)), so:

4-3(3b+7)

determiningTheFunctionDomain
-3(3b+7)+4

We multiply parentheses

-9b-21+4

We add all the numbers together, and all the variables

-9b-17

Back to the equation:

-(-9b-17)



We get rid of parentheses

-3(4-(3b+3))+9b+17=0

We add all the numbers together, and all the variables

9b-3(4-(3b+3))+17=0

We move all terms containing b to the left, all other terms to the right

9b-3(4-(3b+3))=-17

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