-3(4-2b)=(3b+6)

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Solution for -3(4-2b)=(3b+6) equation: 



-3(4-2b)=(3b+6)

We move all terms to the left:

-3(4-2b)-((3b+6))=0

We add all the numbers together, and all the variables

-3(-2b+4)-((3b+6))=0

We multiply parentheses

6b-((3b+6))-12=0



We calculate terms in parentheses: -((3b+6)), so:

(3b+6)

We get rid of parentheses

3b+6

Back to the equation:

-(3b+6)



We get rid of parentheses

6b-3b-6-12=0

We add all the numbers together, and all the variables

3b-18=0

We move all terms containing b to the left, all other terms to the right

3b=18

b=18/3

b=6

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