-3(4-4y)=6(2y-2)

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Solution for -3(4-4y)=6(2y-2) equation: 



-3(4-4y)=6(2y-2)

We move all terms to the left:

-3(4-4y)-(6(2y-2))=0

We add all the numbers together, and all the variables

-3(-4y+4)-(6(2y-2))=0

We multiply parentheses

12y-(6(2y-2))-12=0



We calculate terms in parentheses: -(6(2y-2)), so:

6(2y-2)

We multiply parentheses

12y-12

Back to the equation:

-(12y-12)



We get rid of parentheses

12y-12y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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