-3(4b+1)+(13-4)=0

Solution for -3(4b+1)+(13-4)=0 equation:

Simplifying
-3(4b + 1) + (13 + -4) = 0

Reorder the terms:
-3(1 + 4b) + (13 + -4) = 0
(1 * -3 + 4b * -3) + (13 + -4) = 0
(-3 + -12b) + (13 + -4) = 0

Combine like terms: 13 + -4 = 9
-3 + -12b + (9) = 0
-3 + -12b + 9 = 0

Reorder the terms:
-3 + 9 + -12b = 0

Combine like terms: -3 + 9 = 6
6 + -12b = 0

Solving
6 + -12b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -12b = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -12b = 0 + -6
-12b = 0 + -6

Combine like terms: 0 + -6 = -6
-12b = -6

Divide each side by '-12'.
b = 0.5

Simplifying
b = 0.5