-3(4b+1)+(13b-4)=0

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Solution for -3(4b+1)+(13b-4)=0 equation:


Simplifying
-3(4b + 1) + (13b + -4) = 0

Reorder the terms:
-3(1 + 4b) + (13b + -4) = 0
(1 * -3 + 4b * -3) + (13b + -4) = 0
(-3 + -12b) + (13b + -4) = 0

Reorder the terms:
-3 + -12b + (-4 + 13b) = 0

Remove parenthesis around (-4 + 13b)
-3 + -12b + -4 + 13b = 0

Reorder the terms:
-3 + -4 + -12b + 13b = 0

Combine like terms: -3 + -4 = -7
-7 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-7 + 1b = 0

Solving
-7 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '7' to each side of the equation.
-7 + 7 + 1b = 0 + 7

Combine like terms: -7 + 7 = 0
0 + 1b = 0 + 7
1b = 0 + 7

Combine like terms: 0 + 7 = 7
1b = 7

Divide each side by '1'.
b = 7

Simplifying
b = 7

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