-3(4b+1)+(13b-9)=0

Solution for -3(4b+1)+(13b-9)=0 equation:

Simplifying
-3(4b + 1) + (13b + -9) = 0

Reorder the terms:
-3(1 + 4b) + (13b + -9) = 0
(1 * -3 + 4b * -3) + (13b + -9) = 0
(-3 + -12b) + (13b + -9) = 0

Reorder the terms:
-3 + -12b + (-9 + 13b) = 0

Remove parenthesis around (-9 + 13b)
-3 + -12b + -9 + 13b = 0

Reorder the terms:
-3 + -9 + -12b + 13b = 0

Combine like terms: -3 + -9 = -12
-12 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-12 + 1b = 0

Solving
-12 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 1b = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 1b = 0 + 12
1b = 0 + 12

Combine like terms: 0 + 12 = 12
1b = 12

Divide each side by '1'.
b = 12

Simplifying
b = 12