-3(4b+2)+(13b-5)=0

Solution for -3(4b+2)+(13b-5)=0 equation:

Simplifying
-3(4b + 2) + (13b + -5) = 0

Reorder the terms:
-3(2 + 4b) + (13b + -5) = 0
(2 * -3 + 4b * -3) + (13b + -5) = 0
(-6 + -12b) + (13b + -5) = 0

Reorder the terms:
-6 + -12b + (-5 + 13b) = 0

Remove parenthesis around (-5 + 13b)
-6 + -12b + -5 + 13b = 0

Reorder the terms:
-6 + -5 + -12b + 13b = 0

Combine like terms: -6 + -5 = -11
-11 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-11 + 1b = 0

Solving
-11 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 1b = 0 + 11

Combine like terms: -11 + 11 = 0
0 + 1b = 0 + 11
1b = 0 + 11

Combine like terms: 0 + 11 = 11
1b = 11

Divide each side by '1'.
b = 11

Simplifying
b = 11