-3(4b-5)-4(b+3)=-61

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Solution for -3(4b-5)-4(b+3)=-61 equation: 



-3(4b-5)-4(b+3)=-61

We move all terms to the left:

-3(4b-5)-4(b+3)-(-61)=0

We add all the numbers together, and all the variables

-3(4b-5)-4(b+3)+61=0

We multiply parentheses

-12b-4b+15-12+61=0

We add all the numbers together, and all the variables

-16b+64=0

We move all terms containing b to the left, all other terms to the right

-16b=-64

b=-64/-16

b=+4

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