-3(4f+9)=1/4(8-48f)

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Solution for -3(4f+9)=1/4(8-48f) equation: 



-3(4f+9)=1/4(8-48f)

We move all terms to the left:

-3(4f+9)-(1/4(8-48f))=0



Domain of the equation: 4(8-48f))!=0

f∈R



We add all the numbers together, and all the variables

-3(4f+9)-(1/4(-48f+8))=0

We multiply parentheses

-12f-(1/4(-48f+8))-27=0

We multiply all the terms by the denominator


-12f*4(-48f+8))-(1-27*4(-48f+8))=0

Wy multiply elements

-48f^2(--108f(-=0

We use the square of the difference formula

-48f^2(+108f(-=0

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