-3(4f-5)=5(6-2f)

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Solution for -3(4f-5)=5(6-2f) equation:



-3(4f-5)=5(6-2f)
We move all terms to the left:
-3(4f-5)-(5(6-2f))=0
We add all the numbers together, and all the variables
-3(4f-5)-(5(-2f+6))=0
We multiply parentheses
-12f-(5(-2f+6))+15=0
We calculate terms in parentheses: -(5(-2f+6)), so:
5(-2f+6)
We multiply parentheses
-10f+30
Back to the equation:
-(-10f+30)
We get rid of parentheses
-12f+10f-30+15=0
We add all the numbers together, and all the variables
-2f-15=0
We move all terms containing f to the left, all other terms to the right
-2f=15
f=15/-2
f=-7+1/2

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