-3(4q-9)=q-7(-8q+6)

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Solution for -3(4q-9)=q-7(-8q+6) equation: 



-3(4q-9)=q-7(-8q+6)

We move all terms to the left:

-3(4q-9)-(q-7(-8q+6))=0

We multiply parentheses

-12q-(q-7(-8q+6))+27=0



We calculate terms in parentheses: -(q-7(-8q+6)), so:

q-7(-8q+6)

We multiply parentheses

q+56q-42

We add all the numbers together, and all the variables

57q-42

Back to the equation:

-(57q-42)



We get rid of parentheses

-12q-57q+42+27=0

We add all the numbers together, and all the variables

-69q+69=0

We move all terms containing q to the left, all other terms to the right

-69q=-69

q=-69/-69

q=1

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