-3(4q-9)=q-7(-8q+6)

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Solution for -3(4q-9)=q-7(-8q+6) equation:



-3(4q-9)=q-7(-8q+6)
We move all terms to the left:
-3(4q-9)-(q-7(-8q+6))=0
We multiply parentheses
-12q-(q-7(-8q+6))+27=0
We calculate terms in parentheses: -(q-7(-8q+6)), so:
q-7(-8q+6)
We multiply parentheses
q+56q-42
We add all the numbers together, and all the variables
57q-42
Back to the equation:
-(57q-42)
We get rid of parentheses
-12q-57q+42+27=0
We add all the numbers together, and all the variables
-69q+69=0
We move all terms containing q to the left, all other terms to the right
-69q=-69
q=-69/-69
q=1

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