-3(4t+3)+4(6t+1)=15

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Solution for -3(4t+3)+4(6t+1)=15 equation: 



-3(4t+3)+4(6t+1)=15

We move all terms to the left:

-3(4t+3)+4(6t+1)-(15)=0

We multiply parentheses

-12t+24t-9+4-15=0

We add all the numbers together, and all the variables

12t-20=0

We move all terms containing t to the left, all other terms to the right

12t=20

t=20/12

t=1+2/3

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