-3(4t+5)=3(3-2t)+12

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Solution for -3(4t+5)=3(3-2t)+12 equation:



-3(4t+5)=3(3-2t)+12
We move all terms to the left:
-3(4t+5)-(3(3-2t)+12)=0
We add all the numbers together, and all the variables
-3(4t+5)-(3(-2t+3)+12)=0
We multiply parentheses
-12t-(3(-2t+3)+12)-15=0
We calculate terms in parentheses: -(3(-2t+3)+12), so:
3(-2t+3)+12
We multiply parentheses
-6t+9+12
We add all the numbers together, and all the variables
-6t+21
Back to the equation:
-(-6t+21)
We get rid of parentheses
-12t+6t-21-15=0
We add all the numbers together, and all the variables
-6t-36=0
We move all terms containing t to the left, all other terms to the right
-6t=36
t=36/-6
t=-6

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