-3(4u-2)+8u=6+2(4u-7)

Solution for -3(4u-2)+8u=6+2(4u-7) equation:

-3(4u-2)+8u=6+2(4u-7)

We move all terms to the left:

-3(4u-2)+8u-(6+2(4u-7))=0

We add all the numbers together, and all the variables

8u-3(4u-2)-(6+2(4u-7))=0

We multiply parentheses

8u-12u-(6+2(4u-7))+6=0


We calculate terms in parentheses: -(6+2(4u-7)), so:

6+2(4u-7)

determiningTheFunctionDomain
2(4u-7)+6

We multiply parentheses

8u-14+6

We add all the numbers together, and all the variables

8u-8

Back to the equation:

-(8u-8)


We add all the numbers together, and all the variables

-4u-(8u-8)+6=0

We get rid of parentheses

-4u-8u+8+6=0

We add all the numbers together, and all the variables

-12u+14=0

We move all terms containing u to the left, all other terms to the right

-12u=-14

u=-14/-12

u=1+1/6