-3(4x+3)+4(6x+1)=19

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Solution for -3(4x+3)+4(6x+1)=19 equation: 



-3(4x+3)+4(6x+1)=19

We move all terms to the left:

-3(4x+3)+4(6x+1)-(19)=0

We multiply parentheses

-12x+24x-9+4-19=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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