-3(4x-2)+(5x-8)=-8+(2x+3)

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Solution for -3(4x-2)+(5x-8)=-8+(2x+3) equation: 



-3(4x-2)+(5x-8)=-8+(2x+3)

We move all terms to the left:

-3(4x-2)+(5x-8)-(-8+(2x+3))=0

We multiply parentheses

-12x+(5x-8)-(-8+(2x+3))+6=0

We get rid of parentheses

-12x+5x-(-8+(2x+3))-8+6=0



We calculate terms in parentheses: -(-8+(2x+3)), so:

-8+(2x+3)

determiningTheFunctionDomain
(2x+3)-8

We get rid of parentheses

2x+3-8

We add all the numbers together, and all the variables

2x-5

Back to the equation:

-(2x-5)



We add all the numbers together, and all the variables

-7x-(2x-5)-2=0

We get rid of parentheses

-7x-2x+5-2=0

We add all the numbers together, and all the variables

-9x+3=0

We move all terms containing x to the left, all other terms to the right

-9x=-3

x=-3/-9

x=1/3

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