-3(4x-2)=2x(3x-1)+18

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Solution for -3(4x-2)=2x(3x-1)+18 equation: 



-3(4x-2)=2x(3x-1)+18

We move all terms to the left:

-3(4x-2)-(2x(3x-1)+18)=0

We multiply parentheses

-12x-(2x(3x-1)+18)+6=0



We calculate terms in parentheses: -(2x(3x-1)+18), so:

2x(3x-1)+18

We multiply parentheses

6x^2-2x+18

Back to the equation:

-(6x^2-2x+18)



We get rid of parentheses

-6x^2-12x+2x-18+6=0

We add all the numbers together, and all the variables

-6x^2-10x-12=0

a = -6; b = -10; c = -12;
Δ = b2-4ac
Δ = -102-4·(-6)·(-12)
Δ = -188
Delta is less than zero, so there is no solution for the equation

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