-3(4x-4)+5x=8+4(2x-2)

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Solution for -3(4x-4)+5x=8+4(2x-2) equation: 



-3(4x-4)+5x=8+4(2x-2)

We move all terms to the left:

-3(4x-4)+5x-(8+4(2x-2))=0

We add all the numbers together, and all the variables

5x-3(4x-4)-(8+4(2x-2))=0

We multiply parentheses

5x-12x-(8+4(2x-2))+12=0



We calculate terms in parentheses: -(8+4(2x-2)), so:

8+4(2x-2)

determiningTheFunctionDomain
4(2x-2)+8

We multiply parentheses

8x-8+8

We add all the numbers together, and all the variables

8x

Back to the equation:

-(8x)



We add all the numbers together, and all the variables

-15x+12=0

We move all terms containing x to the left, all other terms to the right

-15x=-12

x=-12/-15

x=4/5

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