-3(4y+1)=4(5-3y)-23

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Solution for -3(4y+1)=4(5-3y)-23 equation:


Simplifying
-3(4y + 1) = 4(5 + -3y) + -23

Reorder the terms:
-3(1 + 4y) = 4(5 + -3y) + -23
(1 * -3 + 4y * -3) = 4(5 + -3y) + -23
(-3 + -12y) = 4(5 + -3y) + -23
-3 + -12y = (5 * 4 + -3y * 4) + -23
-3 + -12y = (20 + -12y) + -23

Reorder the terms:
-3 + -12y = 20 + -23 + -12y

Combine like terms: 20 + -23 = -3
-3 + -12y = -3 + -12y

Add '3' to each side of the equation.
-3 + 3 + -12y = -3 + 3 + -12y

Combine like terms: -3 + 3 = 0
0 + -12y = -3 + 3 + -12y
-12y = -3 + 3 + -12y

Combine like terms: -3 + 3 = 0
-12y = 0 + -12y
-12y = -12y

Add '12y' to each side of the equation.
-12y + 12y = -12y + 12y

Combine like terms: -12y + 12y = 0
0 = -12y + 12y

Combine like terms: -12y + 12y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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