-3(4y+2)+y=38

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Solution for -3(4y+2)+y=38 equation: 



-3(4y+2)+y=38

We move all terms to the left:

-3(4y+2)+y-(38)=0

We add all the numbers together, and all the variables

y-3(4y+2)-38=0

We multiply parentheses

y-12y-6-38=0

We add all the numbers together, and all the variables

-11y-44=0

We move all terms containing y to the left, all other terms to the right

-11y=44

y=44/-11

y=-4

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