-3(4y+2)+y=38

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Solution for -3(4y+2)+y=38 equation:



-3(4y+2)+y=38
We move all terms to the left:
-3(4y+2)+y-(38)=0
We add all the numbers together, and all the variables
y-3(4y+2)-38=0
We multiply parentheses
y-12y-6-38=0
We add all the numbers together, and all the variables
-11y-44=0
We move all terms containing y to the left, all other terms to the right
-11y=44
y=44/-11
y=-4

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