-3(4y-2)+4(-3y)=3(y+2)

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Solution for -3(4y-2)+4(-3y)=3(y+2) equation: 



-3(4y-2)+4(-3y)=3(y+2)

We move all terms to the left:

-3(4y-2)+4(-3y)-(3(y+2))=0

We multiply parentheses

-12y-12y-(3(y+2))+6=0



We calculate terms in parentheses: -(3(y+2)), so:

3(y+2)

We multiply parentheses

3y+6

Back to the equation:

-(3y+6)



We add all the numbers together, and all the variables

-24y-(3y+6)+6=0

We get rid of parentheses

-24y-3y-6+6=0

We add all the numbers together, and all the variables

-27y=0

y=0/-27

y=0

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