-3(4y-2)+5y=3+2(4y-3)

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Solution for -3(4y-2)+5y=3+2(4y-3) equation: 



-3(4y-2)+5y=3+2(4y-3)

We move all terms to the left:

-3(4y-2)+5y-(3+2(4y-3))=0

We add all the numbers together, and all the variables

5y-3(4y-2)-(3+2(4y-3))=0

We multiply parentheses

5y-12y-(3+2(4y-3))+6=0



We calculate terms in parentheses: -(3+2(4y-3)), so:

3+2(4y-3)

determiningTheFunctionDomain
2(4y-3)+3

We multiply parentheses

8y-6+3

We add all the numbers together, and all the variables

8y-3

Back to the equation:

-(8y-3)



We add all the numbers together, and all the variables

-7y-(8y-3)+6=0

We get rid of parentheses

-7y-8y+3+6=0

We add all the numbers together, and all the variables

-15y+9=0

We move all terms containing y to the left, all other terms to the right

-15y=-9

y=-9/-15

y=3/5

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