-3(4y-2)-7=-4(y-2)

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Solution for -3(4y-2)-7=-4(y-2) equation:



-3(4y-2)-7=-4(y-2)
We move all terms to the left:
-3(4y-2)-7-(-4(y-2))=0
We multiply parentheses
-12y-(-4(y-2))+6-7=0
We calculate terms in parentheses: -(-4(y-2)), so:
-4(y-2)
We multiply parentheses
-4y+8
Back to the equation:
-(-4y+8)
We add all the numbers together, and all the variables
-12y-(-4y+8)-1=0
We get rid of parentheses
-12y+4y-8-1=0
We add all the numbers together, and all the variables
-8y-9=0
We move all terms containing y to the left, all other terms to the right
-8y=9
y=9/-8
y=-1+1/8

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