-3(4y-2)-y=-3(y-2)

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Solution for -3(4y-2)-y=-3(y-2) equation: 



-3(4y-2)-y=-3(y-2)

We move all terms to the left:

-3(4y-2)-y-(-3(y-2))=0

We add all the numbers together, and all the variables

-1y-3(4y-2)-(-3(y-2))=0

We multiply parentheses

-1y-12y-(-3(y-2))+6=0



We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We add all the numbers together, and all the variables

-13y-(-3y+6)+6=0

We get rid of parentheses

-13y+3y-6+6=0

We add all the numbers together, and all the variables

-10y=0

y=0/-10

y=0

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