-3(4y-3)+8y=6+2(4y-6)

Solution for -3(4y-3)+8y=6+2(4y-6) equation:

-3(4y-3)+8y=6+2(4y-6)

We move all terms to the left:

-3(4y-3)+8y-(6+2(4y-6))=0

We add all the numbers together, and all the variables

8y-3(4y-3)-(6+2(4y-6))=0

We multiply parentheses

8y-12y-(6+2(4y-6))+9=0


We calculate terms in parentheses: -(6+2(4y-6)), so:

6+2(4y-6)

determiningTheFunctionDomain
2(4y-6)+6

We multiply parentheses

8y-12+6

We add all the numbers together, and all the variables

8y-6

Back to the equation:

-(8y-6)


We add all the numbers together, and all the variables

-4y-(8y-6)+9=0

We get rid of parentheses

-4y-8y+6+9=0

We add all the numbers together, and all the variables

-12y+15=0

We move all terms containing y to the left, all other terms to the right

-12y=-15

y=-15/-12

y=1+1/4