-3(4y-3)-y=-4(y-4)

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Solution for -3(4y-3)-y=-4(y-4) equation: 



-3(4y-3)-y=-4(y-4)

We move all terms to the left:

-3(4y-3)-y-(-4(y-4))=0

We add all the numbers together, and all the variables

-1y-3(4y-3)-(-4(y-4))=0

We multiply parentheses

-1y-12y-(-4(y-4))+9=0



We calculate terms in parentheses: -(-4(y-4)), so:

-4(y-4)

We multiply parentheses

-4y+16

Back to the equation:

-(-4y+16)



We add all the numbers together, and all the variables

-13y-(-4y+16)+9=0

We get rid of parentheses

-13y+4y-16+9=0

We add all the numbers together, and all the variables

-9y-7=0

We move all terms containing y to the left, all other terms to the right

-9y=7

y=7/-9

y=-7/9

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