-3(4y-5)+2(2y-5)=-2(3y-8)-3(y+4)

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Solution for -3(4y-5)+2(2y-5)=-2(3y-8)-3(y+4) equation:



-3(4y-5)+2(2y-5)=-2(3y-8)-3(y+4)
We move all terms to the left:
-3(4y-5)+2(2y-5)-(-2(3y-8)-3(y+4))=0
We multiply parentheses
-12y+4y-(-2(3y-8)-3(y+4))+15-10=0
We calculate terms in parentheses: -(-2(3y-8)-3(y+4)), so:
-2(3y-8)-3(y+4)
We multiply parentheses
-6y-3y+16-12
We add all the numbers together, and all the variables
-9y+4
Back to the equation:
-(-9y+4)
We add all the numbers together, and all the variables
-8y-(-9y+4)+5=0
We get rid of parentheses
-8y+9y-4+5=0
We add all the numbers together, and all the variables
y+1=0
We move all terms containing y to the left, all other terms to the right
y=-1

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