-3(4y-6)+4y=7(y+3)

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Solution for -3(4y-6)+4y=7(y+3) equation: 



-3(4y-6)+4y=7(y+3)

We move all terms to the left:

-3(4y-6)+4y-(7(y+3))=0

We add all the numbers together, and all the variables

4y-3(4y-6)-(7(y+3))=0

We multiply parentheses

4y-12y-(7(y+3))+18=0



We calculate terms in parentheses: -(7(y+3)), so:

7(y+3)

We multiply parentheses

7y+21

Back to the equation:

-(7y+21)



We add all the numbers together, and all the variables

-8y-(7y+21)+18=0

We get rid of parentheses

-8y-7y-21+18=0

We add all the numbers together, and all the variables

-15y-3=0

We move all terms containing y to the left, all other terms to the right

-15y=3

y=3/-15

y=-1/5

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