-3(4y-6)-y=-2(y-4)

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Solution for -3(4y-6)-y=-2(y-4) equation:



-3(4y-6)-y=-2(y-4)
We move all terms to the left:
-3(4y-6)-y-(-2(y-4))=0
We add all the numbers together, and all the variables
-1y-3(4y-6)-(-2(y-4))=0
We multiply parentheses
-1y-12y-(-2(y-4))+18=0
We calculate terms in parentheses: -(-2(y-4)), so:
-2(y-4)
We multiply parentheses
-2y+8
Back to the equation:
-(-2y+8)
We add all the numbers together, and all the variables
-13y-(-2y+8)+18=0
We get rid of parentheses
-13y+2y-8+18=0
We add all the numbers together, and all the variables
-11y+10=0
We move all terms containing y to the left, all other terms to the right
-11y=-10
y=-10/-11
y=10/11

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