-3(4y-8)-y=-2(y-4)

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Solution for -3(4y-8)-y=-2(y-4) equation: 



-3(4y-8)-y=-2(y-4)

We move all terms to the left:

-3(4y-8)-y-(-2(y-4))=0

We add all the numbers together, and all the variables

-1y-3(4y-8)-(-2(y-4))=0

We multiply parentheses

-1y-12y-(-2(y-4))+24=0



We calculate terms in parentheses: -(-2(y-4)), so:

-2(y-4)

We multiply parentheses

-2y+8

Back to the equation:

-(-2y+8)



We add all the numbers together, and all the variables

-13y-(-2y+8)+24=0

We get rid of parentheses

-13y+2y-8+24=0

We add all the numbers together, and all the variables

-11y+16=0

We move all terms containing y to the left, all other terms to the right

-11y=-16

y=-16/-11

y=1+5/11

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