-3(4z+3)+4(6z+1)=43

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Solution for -3(4z+3)+4(6z+1)=43 equation: 



-3(4z+3)+4(6z+1)=43

We move all terms to the left:

-3(4z+3)+4(6z+1)-(43)=0

We multiply parentheses

-12z+24z-9+4-43=0

We add all the numbers together, and all the variables

12z-48=0

We move all terms containing z to the left, all other terms to the right

12z=48

z=48/12

z=4

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